Name:
All American Patriot!pE.tl5DNpI2020-08-26 18:20
I'm gonna be using a name and tripcode for now on and if none of you bastards like that then you can all go home to your mommas cry. I've lurked here as anon longer enough and now it's time for some sort of identity. Ya bastards need someone to put you in your place with all of this racist shit you post. If you don't like me get in line because I have a load of asswhippings to dish out.
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Anonymous2021-02-14 12:58
Kill yourself
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RAPE NIGGUHS2026-03-19 8:35
Have you done your civic duty today, maggot? If not I will help you! *pulls down pants and bends over*
u/Ill-Championship-506 avatar Ill-Championship-506 • 1d ago
Geometrically, yes, but practically no. Even though the energy initially spreads in all directions, the shock wave itself never appears as a perfect sphere. This is due to many factors, such as the Mach stem, the precursor, atmospheric densities at different altitudes, turbulence, wind conditions, and much more. This is why a single formula is never used to estimate the shock wave radius in real military calculations. If you need to calculate the radius for 100 and 800 kilotons, and do it very quickly and only consider the yield and radius, then the cube root works well. But if your calculation includes a real atmosphere, then it's better to use at least the Broad equations and the Rankine-Hugoniot equation. You can also use the Whitham equation, as it takes into account terrain and obstacles, which is very important in urban environments.
